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Problem Solutions

  




 

 

Exercises

  1. All Dice Combinations. Write a list comprehension that uses nested for-clauses to create a single list with all 36 different dice combinations from (1,1) to (6,6).

  2. Temperature Table. Writea list comprehension that creates a list of tuples. Each tuple has two values, a temperature in Farenheit and a temperature in Celsius.

    Create one list for Farenheit values from 0 to 100 in steps of 5 and the matching Celsius values.

    Create another list for Celsius values from -10 to 50 in steps of 2 and the matching Farenheit values.

  3. Define max() and min(). Use reduce to create versions of the built-ins max and min.

    You may find this difficult to do this with a simple lambda form. However, consider the following. We can pick a value from a tuple like this: (a,b)[0] == a, and (a,b)[1] == b. What are the values of (a,b)[a<b] and (a,b)[a>b]?

  4. Compute the Average or Mean. A number of standard descriptive statistics can be built with reduce. These include mean and standard deviation. The basic formulae are given in Chapter 13, Tuples .

    Mean is a simple “add-reduction” of the values in a sequence divided by the length.

  5. Compute the Variance and Standard Deviation. A number of standard descriptive statistics can be built with reduce. These include mean and standard deviation. The basic formulae are given in Chapter 13, Tuples .

    The standard deviation has a number of alternative definitions. One approach is to sum the values and square this number, as well as sum the squares of each number. Summing squares can be done as a map to compute squares and then use a sum function based on reduce. Or summing squares can be done with a special reduce that both squares and sums.

    Also the standard deviation can be defined as the square root of the variance, which is computed as:

    Procedure 20.1. Variance of a sequence a

    1. Mean. m ← mean(a)

    2. Total Variance. s ← sum of (a[i] − m )2 for all i

    3. Average Variance. divide s by n−1

  6. Compute the Mode. The mode function finds the most common value in a data set. This can be done by computing the frequency with which each unique value occurs and sorting that list to find the most common value. The frequency distribution is easiest done using a mapping, something we'll cover in the next chapter. This can be simplified also using the advanced list sorting in the next section of this chapter.

    Procedure 20.2. Mode of a sequence, a

    1. Initialization

      fqList ← empty list

    2. For each value, v in a

      1. If v is element 0 of one of the tuples of fqList, then

        Get the frequency, f, element 1 of the tuple.

        Remove the tuple (v,f) from fqList.

        Create a new tuple (v,f+1).

        Add the new tuple to the fqList.

      2. If v is not element 0 of one of the tuples of fqList, then

        Create a new tuple (v,1).

        Add the new tuple to the fqList.

    3. Save tuple 0 of the fqList as the largest tuple, maxFq.

    4. For each frequency, t in fqList

      1. If t's frequency is larger than the frequency of maxFq, then

        maxFqt.

    5. Return maxFq as the modal value and the frequency with which it occurs.

  7. Compute the Median. The median function arranges the values in sorted order. It locates either the mid-most value (if there are an odd number) or it averages two adjacent values (if there are an even number).

    If len(data) % 2 == 1, there is an odd number of values, and (len(data)+1)/2 is the midmost value. Otherwise there is an even number of values, and the len(data)/2 and len(data)/2-1 are the two mid-most values which must be averaged.

  8. Unique Values In A Sequence. In Accumulating Unique Values, we looked at accumulating the unique values in a sequence. Sorting the sequence leads to a purely superficial simplification. Sorting is a relatively expensive operation, but for short sequences, the cost is not much higher than the version already presented.

    Given an input sequence, seq, we can easily sort this sequence. This will put all equal-valued elements together. The comparison for unique values is now done between adjacent values, instead of a lookup in the resulting sequence.

    Procedure 20.3. Unique Values of a Sequence, seq , using sort

    1. Initalize

      set result ← an empty sequence.

      Sort the input sequence, seq .

    2. Loop. For each value, v, in seq .

      1. Already in resultIs v the last element in result? If so, ignore it. If not, append v to the sequence result.

    3. Result. Return array result, which has unique values from seq .

  9. Portfolio Reporting. In Blocks of Stock, we presented a stock portfolio as a sequence of tuples. Plus, we wrote two simple functions to evaluate purchase price and total gain or loss for this portfolio.

    Develop a function (or a lambda form) to sort this porfolio into ascending order by current value (current price * number of shares). This function (or lambda) will require comparing the products of two fields instead of simply comparing two fields.

  10. Matrix Formatting. Given a 6×6 matrix of dice rolls, produce a nicely formatted result. Each cell should be printed with a format like "| %2s" so that vertical lines separate the columns. Each row should end with an '|'. The top and bottom should have rows of "----"'s printed to make a complete table.

  11. Three Dimensions. If the rolls of two dice can be expressed in a two-dimensional table, then the rolls of three dice can be expressed in a three-dimensional table. Develop a three dimensional table, 6 x 6 x 6, that has all 216 different rolls of three dice.

    Write a loop that extracts the different values and summarizes them in a frequency table. The range of values will be from 3 to 18.


 
 
  Published under the terms of the Open Publication License Design by Interspire