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Problem Solutions

  




 

 

3.6.4. The Rows Holding the Group-wise Maximum of a Certain Field

Task: For each article, find the dealer or dealers with the most expensive price.

This problem can be solved with a subquery like this one:

SELECT article, dealer, price
FROM   shop s1
WHERE  price=(SELECT MAX(s2.price)
              FROM shop s2
              WHERE s1.article = s2.article);

 
 
  Published under the terms of the GNU General Public License Design by Interspire